Titration of Vinegar,These are the calculations that I did in the lab:Titrant (NaOH) concentratio...

Titration of Vinegar,
These are the calculations that I did in the lab:

Titrant (NaOH) concentration: 0.1 m NaOH
Vinegar volume: 2.0 mL vinegar
Initial buret reading (initial NaOH volume): 0.0 mL
Final buret reading (final NaOH volume): 17.7 mL

Here are the questions:

1. Calculate the moles of NaOH using the volume and molarity of NaOH. Show your work. moles = molarity * volume

2. Since the reaction ratio is 1 to 1, the moles of acetic acid in the vinegar is equal to the moles of NaOH reacted during the titration. Calculate the molarity of the acetic acid in the vinegar. Show your work?
Molarity = moles / volume

3. Calculate the grams of acetic acid in the vinegar. Show your work?

4. Assuming that the density of vinegar is very close to 1.0 g/mL, the 2.0 mL sample of vinegar used in the titration should weigh 2.0 g. Use this to calculate the mass % of acetic acid in the vinegar sample.
mass % = (mass acetic acid / mass vinegar) * 100%

Solved
Chemistry 1 Answer ahmad masoud